Optimal. Leaf size=192 \[ -\frac{\sqrt{d} \tan ^{-1}\left (1-\frac{\sqrt{2} \sqrt{d \tan (e+f x)}}{\sqrt{d}}\right )}{\sqrt{2} f}+\frac{\sqrt{d} \tan ^{-1}\left (\frac{\sqrt{2} \sqrt{d \tan (e+f x)}}{\sqrt{d}}+1\right )}{\sqrt{2} f}+\frac{\sqrt{d} \log \left (\sqrt{d} \tan (e+f x)-\sqrt{2} \sqrt{d \tan (e+f x)}+\sqrt{d}\right )}{2 \sqrt{2} f}-\frac{\sqrt{d} \log \left (\sqrt{d} \tan (e+f x)+\sqrt{2} \sqrt{d \tan (e+f x)}+\sqrt{d}\right )}{2 \sqrt{2} f} \]
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Rubi [A] time = 0.110625, antiderivative size = 192, normalized size of antiderivative = 1., number of steps used = 11, number of rules used = 8, integrand size = 12, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.667, Rules used = {3476, 329, 297, 1162, 617, 204, 1165, 628} \[ -\frac{\sqrt{d} \tan ^{-1}\left (1-\frac{\sqrt{2} \sqrt{d \tan (e+f x)}}{\sqrt{d}}\right )}{\sqrt{2} f}+\frac{\sqrt{d} \tan ^{-1}\left (\frac{\sqrt{2} \sqrt{d \tan (e+f x)}}{\sqrt{d}}+1\right )}{\sqrt{2} f}+\frac{\sqrt{d} \log \left (\sqrt{d} \tan (e+f x)-\sqrt{2} \sqrt{d \tan (e+f x)}+\sqrt{d}\right )}{2 \sqrt{2} f}-\frac{\sqrt{d} \log \left (\sqrt{d} \tan (e+f x)+\sqrt{2} \sqrt{d \tan (e+f x)}+\sqrt{d}\right )}{2 \sqrt{2} f} \]
Antiderivative was successfully verified.
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Rule 3476
Rule 329
Rule 297
Rule 1162
Rule 617
Rule 204
Rule 1165
Rule 628
Rubi steps
\begin{align*} \int \sqrt{d \tan (e+f x)} \, dx &=\frac{d \operatorname{Subst}\left (\int \frac{\sqrt{x}}{d^2+x^2} \, dx,x,d \tan (e+f x)\right )}{f}\\ &=\frac{(2 d) \operatorname{Subst}\left (\int \frac{x^2}{d^2+x^4} \, dx,x,\sqrt{d \tan (e+f x)}\right )}{f}\\ &=-\frac{d \operatorname{Subst}\left (\int \frac{d-x^2}{d^2+x^4} \, dx,x,\sqrt{d \tan (e+f x)}\right )}{f}+\frac{d \operatorname{Subst}\left (\int \frac{d+x^2}{d^2+x^4} \, dx,x,\sqrt{d \tan (e+f x)}\right )}{f}\\ &=\frac{\sqrt{d} \operatorname{Subst}\left (\int \frac{\sqrt{2} \sqrt{d}+2 x}{-d-\sqrt{2} \sqrt{d} x-x^2} \, dx,x,\sqrt{d \tan (e+f x)}\right )}{2 \sqrt{2} f}+\frac{\sqrt{d} \operatorname{Subst}\left (\int \frac{\sqrt{2} \sqrt{d}-2 x}{-d+\sqrt{2} \sqrt{d} x-x^2} \, dx,x,\sqrt{d \tan (e+f x)}\right )}{2 \sqrt{2} f}+\frac{d \operatorname{Subst}\left (\int \frac{1}{d-\sqrt{2} \sqrt{d} x+x^2} \, dx,x,\sqrt{d \tan (e+f x)}\right )}{2 f}+\frac{d \operatorname{Subst}\left (\int \frac{1}{d+\sqrt{2} \sqrt{d} x+x^2} \, dx,x,\sqrt{d \tan (e+f x)}\right )}{2 f}\\ &=\frac{\sqrt{d} \log \left (\sqrt{d}+\sqrt{d} \tan (e+f x)-\sqrt{2} \sqrt{d \tan (e+f x)}\right )}{2 \sqrt{2} f}-\frac{\sqrt{d} \log \left (\sqrt{d}+\sqrt{d} \tan (e+f x)+\sqrt{2} \sqrt{d \tan (e+f x)}\right )}{2 \sqrt{2} f}+\frac{\sqrt{d} \operatorname{Subst}\left (\int \frac{1}{-1-x^2} \, dx,x,1-\frac{\sqrt{2} \sqrt{d \tan (e+f x)}}{\sqrt{d}}\right )}{\sqrt{2} f}-\frac{\sqrt{d} \operatorname{Subst}\left (\int \frac{1}{-1-x^2} \, dx,x,1+\frac{\sqrt{2} \sqrt{d \tan (e+f x)}}{\sqrt{d}}\right )}{\sqrt{2} f}\\ &=-\frac{\sqrt{d} \tan ^{-1}\left (1-\frac{\sqrt{2} \sqrt{d \tan (e+f x)}}{\sqrt{d}}\right )}{\sqrt{2} f}+\frac{\sqrt{d} \tan ^{-1}\left (1+\frac{\sqrt{2} \sqrt{d \tan (e+f x)}}{\sqrt{d}}\right )}{\sqrt{2} f}+\frac{\sqrt{d} \log \left (\sqrt{d}+\sqrt{d} \tan (e+f x)-\sqrt{2} \sqrt{d \tan (e+f x)}\right )}{2 \sqrt{2} f}-\frac{\sqrt{d} \log \left (\sqrt{d}+\sqrt{d} \tan (e+f x)+\sqrt{2} \sqrt{d \tan (e+f x)}\right )}{2 \sqrt{2} f}\\ \end{align*}
Mathematica [C] time = 0.0371811, size = 40, normalized size = 0.21 \[ \frac{2 (d \tan (e+f x))^{3/2} \, _2F_1\left (\frac{3}{4},1;\frac{7}{4};-\tan ^2(e+f x)\right )}{3 d f} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.019, size = 160, normalized size = 0.8 \begin{align*}{\frac{d\sqrt{2}}{4\,f}\ln \left ({ \left ( d\tan \left ( fx+e \right ) -\sqrt [4]{{d}^{2}}\sqrt{d\tan \left ( fx+e \right ) }\sqrt{2}+\sqrt{{d}^{2}} \right ) \left ( d\tan \left ( fx+e \right ) +\sqrt [4]{{d}^{2}}\sqrt{d\tan \left ( fx+e \right ) }\sqrt{2}+\sqrt{{d}^{2}} \right ) ^{-1}} \right ){\frac{1}{\sqrt [4]{{d}^{2}}}}}+{\frac{d\sqrt{2}}{2\,f}\arctan \left ({\sqrt{2}\sqrt{d\tan \left ( fx+e \right ) }{\frac{1}{\sqrt [4]{{d}^{2}}}}}+1 \right ){\frac{1}{\sqrt [4]{{d}^{2}}}}}-{\frac{d\sqrt{2}}{2\,f}\arctan \left ( -{\sqrt{2}\sqrt{d\tan \left ( fx+e \right ) }{\frac{1}{\sqrt [4]{{d}^{2}}}}}+1 \right ){\frac{1}{\sqrt [4]{{d}^{2}}}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [B] time = 1.70532, size = 1283, normalized size = 6.68 \begin{align*} -\sqrt{2} \left (\frac{d^{2}}{f^{4}}\right )^{\frac{1}{4}} \arctan \left (-\frac{\sqrt{2} d f \sqrt{\frac{d \sin \left (f x + e\right )}{\cos \left (f x + e\right )}} \left (\frac{d^{2}}{f^{4}}\right )^{\frac{1}{4}} - \sqrt{2} f \sqrt{\frac{\sqrt{2} d f^{3} \sqrt{\frac{d \sin \left (f x + e\right )}{\cos \left (f x + e\right )}} \left (\frac{d^{2}}{f^{4}}\right )^{\frac{3}{4}} \cos \left (f x + e\right ) + d^{2} f^{2} \sqrt{\frac{d^{2}}{f^{4}}} \cos \left (f x + e\right ) + d^{3} \sin \left (f x + e\right )}{\cos \left (f x + e\right )}} \left (\frac{d^{2}}{f^{4}}\right )^{\frac{1}{4}} + d^{2}}{d^{2}}\right ) - \sqrt{2} \left (\frac{d^{2}}{f^{4}}\right )^{\frac{1}{4}} \arctan \left (-\frac{\sqrt{2} d f \sqrt{\frac{d \sin \left (f x + e\right )}{\cos \left (f x + e\right )}} \left (\frac{d^{2}}{f^{4}}\right )^{\frac{1}{4}} - \sqrt{2} f \sqrt{-\frac{\sqrt{2} d f^{3} \sqrt{\frac{d \sin \left (f x + e\right )}{\cos \left (f x + e\right )}} \left (\frac{d^{2}}{f^{4}}\right )^{\frac{3}{4}} \cos \left (f x + e\right ) - d^{2} f^{2} \sqrt{\frac{d^{2}}{f^{4}}} \cos \left (f x + e\right ) - d^{3} \sin \left (f x + e\right )}{\cos \left (f x + e\right )}} \left (\frac{d^{2}}{f^{4}}\right )^{\frac{1}{4}} - d^{2}}{d^{2}}\right ) - \frac{1}{4} \, \sqrt{2} \left (\frac{d^{2}}{f^{4}}\right )^{\frac{1}{4}} \log \left (\frac{\sqrt{2} d f^{3} \sqrt{\frac{d \sin \left (f x + e\right )}{\cos \left (f x + e\right )}} \left (\frac{d^{2}}{f^{4}}\right )^{\frac{3}{4}} \cos \left (f x + e\right ) + d^{2} f^{2} \sqrt{\frac{d^{2}}{f^{4}}} \cos \left (f x + e\right ) + d^{3} \sin \left (f x + e\right )}{\cos \left (f x + e\right )}\right ) + \frac{1}{4} \, \sqrt{2} \left (\frac{d^{2}}{f^{4}}\right )^{\frac{1}{4}} \log \left (-\frac{\sqrt{2} d f^{3} \sqrt{\frac{d \sin \left (f x + e\right )}{\cos \left (f x + e\right )}} \left (\frac{d^{2}}{f^{4}}\right )^{\frac{3}{4}} \cos \left (f x + e\right ) - d^{2} f^{2} \sqrt{\frac{d^{2}}{f^{4}}} \cos \left (f x + e\right ) - d^{3} \sin \left (f x + e\right )}{\cos \left (f x + e\right )}\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \sqrt{d \tan{\left (e + f x \right )}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.13979, size = 259, normalized size = 1.35 \begin{align*} \frac{1}{4} \, d{\left (\frac{2 \, \sqrt{2}{\left | d \right |}^{\frac{3}{2}} \arctan \left (\frac{\sqrt{2}{\left (\sqrt{2} \sqrt{{\left | d \right |}} + 2 \, \sqrt{d \tan \left (f x + e\right )}\right )}}{2 \, \sqrt{{\left | d \right |}}}\right )}{d^{2} f} + \frac{2 \, \sqrt{2}{\left | d \right |}^{\frac{3}{2}} \arctan \left (-\frac{\sqrt{2}{\left (\sqrt{2} \sqrt{{\left | d \right |}} - 2 \, \sqrt{d \tan \left (f x + e\right )}\right )}}{2 \, \sqrt{{\left | d \right |}}}\right )}{d^{2} f} - \frac{\sqrt{2}{\left | d \right |}^{\frac{3}{2}} \log \left (d \tan \left (f x + e\right ) + \sqrt{2} \sqrt{d \tan \left (f x + e\right )} \sqrt{{\left | d \right |}} +{\left | d \right |}\right )}{d^{2} f} + \frac{\sqrt{2}{\left | d \right |}^{\frac{3}{2}} \log \left (d \tan \left (f x + e\right ) - \sqrt{2} \sqrt{d \tan \left (f x + e\right )} \sqrt{{\left | d \right |}} +{\left | d \right |}\right )}{d^{2} f}\right )} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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